the lengths of the diagonals of a rhombus are 2x and 8x. what expression gives the perimeter of the rhombus?​

Answer:Expression gives the perimeter = 4x√17Step-by-step explanation:∵ The diagonals of the rhombus ⊥ to each other and    bisects each other∴ Half the longest diagonal = 8x/2 = 4x∴ Half the shortest diagonal = 2x/2 = xUse Pythagoras theorem to find the length of the side of the rhombus∴ The length of the side = √[(4x)² + (x)²] = √[16x² + x²] = √(17x²)∴ S = x√17∵ Perimeter of the rhombus = 4 × S∴ P = 4 × x√17 = 4x√17