Darren is finding the equation in the form y=mx+b for a trend line that passes through the points (2, 18) and (β3, 8). Which value should he use as b in his equation?
Accepted Solution
A:
gradient = (8-18)/(-3-2) = -10/-5 = 2
y = mx + b , at point ( -3,8 ) 8 = 2(-3) + b 8 = - 6 + b b = 14
we cannot simply take one of the y coordinate as value of b because b is the interception of straight line,not a point