5. Write an equation for the line that is parallel to the given line and that passes through the given point. y = β5x + 3; (β6, 3)
Accepted Solution
A:
Answer:y = -5x - 27Step-by-step explanation:First and foremost, parallel lines have SIMILAR RATE OF CHANGES [SLOPES], so we keep the -5. Moving forward, we simply plug the coordinate into the Slope-Intercept Formula, y = mx + b --> 3 = -5[-6] + b. Our y-intercept is [0, -27], therefore our parallel equation is y = -5x - 27.