find the solution set (x,y,z) of the system:3x-2y+4z=62y-3z=206z=12

Answer:The solution is x = 8, y = 13 and z = 2.Step-by-step explanation:We are given a system of equations with the variables x, y, and z from which we have to solve for x, y, and z. The equations are 3x - 2y + 4z = 6 ........ (1) 2y - 3z = 20 .......... (2) 6z = 12 ......... (3) Now, from equation (3),  we get z = 2. Now, putting z = 2 in equation (2) we get 2y = 20 + 6 = 26  ⇒ y = 13 Now, from equation (1), putting y = 13 and z = 2, we get  3x = 6 - (4 × 2) + (2 × 13) = 24 ⇒ x = 8 So the solution is x = 8, y = 13 and z = 2. (Answer)